MHT CET · Chemistry · Chemical Kinetics
For a reaction \(r=k[A][B]^2\), if concentration of \(A\) is doubled the rate of reaction
- A increases by 2
- B decrease by \(\frac{1}{2}\)
- C increases by 4
- D decreases by 2
Answer & Solution
Correct Answer
(A) increases by 2
Step-by-step Solution
Detailed explanation
\(\begin{aligned}
& \text { Rate }=\mathrm{k}[\mathrm{~A}][\mathrm{B}]^2 \\
& (\text { Rate })_2=\mathrm{k}[2 \mathrm{~A}][\mathrm{B}]^2=\mathrm{k} \times 2[\mathrm{~A}][\mathrm{B}]^2 \\
\therefore \quad & (\text { Rate })_2=2 \times \text { Rate }
\end{aligned}\)
i.e., rate of reaction increases by a factor of 2 .
& \text { Rate }=\mathrm{k}[\mathrm{~A}][\mathrm{B}]^2 \\
& (\text { Rate })_2=\mathrm{k}[2 \mathrm{~A}][\mathrm{B}]^2=\mathrm{k} \times 2[\mathrm{~A}][\mathrm{B}]^2 \\
\therefore \quad & (\text { Rate })_2=2 \times \text { Rate }
\end{aligned}\)
i.e., rate of reaction increases by a factor of 2 .
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