MHT CET · Chemistry · Chemical Kinetics
For a first order reaction, intercept of the graph between \(\log \left(\frac{[\mathrm{A}]_0}{[\mathrm{~A}]_{\mathrm{t}}} \mathrm{Y}\right.\)-axis) and time. (X-axis) is equal to
- A \(-\frac{\mathrm{k}}{2.303 \mathrm{~K}}\)
- B \(-\log [\mathrm{A}]_0\)
- C zero
- D \(\frac{2.303}{\mathrm{~K}}\)
Answer & Solution
Correct Answer
(C) zero
Step-by-step Solution
Detailed explanation
For \(1^{\text {st }}\) order reaction,
\(2.303 \log \frac{[\mathrm{A}]_0}{[\mathrm{~A}]_{\mathrm{t}}}=\mathrm{kt}\)
\(
\log \frac{[\mathrm{A}]_0}{[\mathrm{~A}]_{\mathrm{t}}}=\frac{\mathrm{k}}{2.303} \cdot \mathrm{t}, \mathrm{y}=\mathrm{mx} ; \quad \mathrm{C}=0[\text { Intercept }=0]
\)
\(2.303 \log \frac{[\mathrm{A}]_0}{[\mathrm{~A}]_{\mathrm{t}}}=\mathrm{kt}\)
\(
\log \frac{[\mathrm{A}]_0}{[\mathrm{~A}]_{\mathrm{t}}}=\frac{\mathrm{k}}{2.303} \cdot \mathrm{t}, \mathrm{y}=\mathrm{mx} ; \quad \mathrm{C}=0[\text { Intercept }=0]
\)
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