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MHT CET · Chemistry · Thermodynamics (C)

For a certain reaction \(\Delta H=-225 \mathrm{~kJ}\) and \(\Delta S=-150 \mathrm{JK}^{-1}\). Find the temperature so that \(\Delta \mathrm{G}\) is zero.

  1. A 1500 K
  2. B 1450 K
  3. C 1340 K
  4. D 1300 K
Verified Solution

Answer & Solution

Correct Answer

(A) 1500 K

Step-by-step Solution

Detailed explanation

\( \Delta G = \Delta H - T\Delta S \) \( 0 = -225 \times 10^3 \mathrm{~J} - T(-150 \mathrm{~JK}^{-1}) \)