MHT CET · Chemistry · Thermodynamics (C)
For a certain reaction \(\Delta H=-225 \mathrm{~kJ}\) and \(\Delta S=-150 \mathrm{JK}^{-1}\). Find the temperature so that \(\Delta \mathrm{G}\) is zero.
- A 1500 K
- B 1450 K
- C 1340 K
- D 1300 K
Answer & Solution
Correct Answer
(A) 1500 K
Step-by-step Solution
Detailed explanation
\( \Delta G = \Delta H - T\Delta S \) \( 0 = -225 \times 10^3 \mathrm{~J} - T(-150 \mathrm{~JK}^{-1}) \)
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