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MHT CET · Chemistry · Thermodynamics (C)

For a certain reaction, \(\Delta \mathrm{H}=-210 \mathrm{~kJ}\) and \(\Delta \mathrm{S}=-150 \mathrm{~J} \mathrm{~K}^{-1}\) Find the temperature so that \(\Delta \mathrm{G}=0\)

  1. A 1100 K
  2. B 1200 K
  3. C 1400 K
  4. D 1300 K
Verified Solution

Answer & Solution

Correct Answer

(C) 1400 K

Step-by-step Solution

Detailed explanation

\( \Delta G = \Delta H - T \Delta S \) \( 0 = \Delta H - T \Delta S \)