MHT CET · Chemistry · Thermodynamics (C)
For a certain reaction, \(\Delta \mathrm{H}=-210 \mathrm{~kJ}\) and \(\Delta \mathrm{S}=-150 \mathrm{~J} \mathrm{~K}^{-1}\) Find the temperature so that \(\Delta \mathrm{G}=0\)
- A 1100 K
- B 1200 K
- C 1400 K
- D 1300 K
Answer & Solution
Correct Answer
(C) 1400 K
Step-by-step Solution
Detailed explanation
\( \Delta G = \Delta H - T \Delta S \) \( 0 = \Delta H - T \Delta S \)
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