MHT CET · Chemistry · Thermodynamics (C)
Find work done on 2 mole of an ideal gas at \(27^{\circ} \mathrm{C}\) if it is compressed reversibly and isothermally from \(5.05 \times 10^6 \mathrm{Nm}^{-2}\) to \(1.01 \times 10^5 \mathrm{Nm}^{-2}\) pressure.
- A 19.52 kJ
- B 1.95 kJ
- C 39.04 kJ
- D 3.904 kJ
Answer & Solution
Correct Answer
(A) 19.52 kJ
Step-by-step Solution
Detailed explanation
\(\mathrm{W}_{\max } =-2.303 \mathrm{nRT} \log _{10}\left(\frac{\mathrm{~V}_2}{\mathrm{~V}_{\mathrm{i}}}\right) \)
\( =-2.303 \times 2 \mathrm{~mol} \times 8.314 \mathrm{JK}^{-1} \mathrm{~mol}^{-1} \times 300 \mathrm{~K} \)
\( \log _{10} \frac{1.01 \times 10^5}{5.05 \times 10^6} \)
\( =19.52 \mathrm{~kJ}\)
\( =-2.303 \times 2 \mathrm{~mol} \times 8.314 \mathrm{JK}^{-1} \mathrm{~mol}^{-1} \times 300 \mathrm{~K} \)
\( \log _{10} \frac{1.01 \times 10^5}{5.05 \times 10^6} \)
\( =19.52 \mathrm{~kJ}\)
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