MHT CET · Chemistry · Thermodynamics (C)
Find value of Q from following equations. (i) \(\mathrm{C}_{(\mathrm{s})}+\mathrm{O}_{2(\mathrm{~g})} \longrightarrow \mathrm{CO}_{2(\mathrm{~g})} \Delta \mathrm{H}=\mathrm{QkJ}\) (ii) \(\mathrm{C}_{(\mathrm{s})}+\frac{1}{2} \mathrm{O}_{2(\mathrm{~g})} \longrightarrow \mathrm{CO}_{2(\mathrm{~g})} \Delta \mathrm{H}=-\mathrm{xkJ}\) (iii) \(\mathrm{C}_{(\mathrm{s})}+\frac{1}{2} \mathrm{O}_{2(\mathrm{~g})} \longrightarrow \mathrm{CO}_{2(\mathrm{~g})} \cdot \Delta \mathrm{H}=-\mathrm{ykJ}\)
- A \(-(x+y) k J\)
- B \((x-y) k J\)
- C \(\frac{-\mathrm{x}+\mathrm{y}}{2} \mathrm{~kJ}\)
- D \(\frac{\mathrm{x}+\mathrm{y}}{2} \mathrm{~kJ}\)
Answer & Solution
Correct Answer
(A) \(-(x+y) k J\)
Step-by-step Solution
Detailed explanation
(ii) \(\mathrm{C}_{(\mathrm{s})}+\frac{1}{2} \mathrm{O}_{2(\mathrm{~g})} \longrightarrow \mathrm{CO}_{(\mathrm{g})} \quad \Delta \mathrm{H}=-\mathrm{x}\)
(iii) \(\mathrm{CO}_{(\mathrm{g})}+\frac{1}{2} \mathrm{O}_{2(\mathrm{~g})} \longrightarrow \mathrm{CO}_{2(\mathrm{~g})} \quad \Delta \mathrm{H}=-\mathrm{y}\)
Adding equations (ii) and (iii), we get the required equation;
(i) \(\mathrm{C}_{(\mathrm{s})}+\mathrm{O}_{2(\mathrm{~g})} \longrightarrow \mathrm{CO}_{2(\mathrm{~g})} \Delta \mathrm{H}=\mathrm{Q}=-(\mathrm{x}+\mathrm{y}) \mathrm{kJ}\)
[Note: The equation (ii) and (iii) from the question is modified to apply appropriate textual concepts.]
(iii) \(\mathrm{CO}_{(\mathrm{g})}+\frac{1}{2} \mathrm{O}_{2(\mathrm{~g})} \longrightarrow \mathrm{CO}_{2(\mathrm{~g})} \quad \Delta \mathrm{H}=-\mathrm{y}\)
Adding equations (ii) and (iii), we get the required equation;
(i) \(\mathrm{C}_{(\mathrm{s})}+\mathrm{O}_{2(\mathrm{~g})} \longrightarrow \mathrm{CO}_{2(\mathrm{~g})} \Delta \mathrm{H}=\mathrm{Q}=-(\mathrm{x}+\mathrm{y}) \mathrm{kJ}\)
[Note: The equation (ii) and (iii) from the question is modified to apply appropriate textual concepts.]
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