MHT CET · Chemistry · States of Matter
Find the temperature in degree Celsius if volume and pressure of 2 mole ideal gas is \(20 \mathrm{dm}^3\) and 4.926 atmospheres respectively.
\(\left(\mathrm{R}=0-0821 \mathrm{dm}^3 \mathrm{~atm} \mathrm{~K} \mathrm{mol}^{-1}\right)\)
- A \(273\)
- B \(327\)
- C \(600\)
- D \(453\)
Answer & Solution
Correct Answer
(B) \(327\)
Step-by-step Solution
Detailed explanation
According to ideal gas equation,
\(
\begin{aligned}
\mathrm{PV} & =\mathrm{nRT} \\
\therefore \mathrm{T} & =\frac{\mathrm{PV}}{\mathrm{nR}}=\frac{4.926 \times 20}{12 \times 0.0821} \\
\mathrm{~T} & =600 \mathrm{~K}
\end{aligned}
\)
Temp. in \({ }^{\circ} \mathrm{C}=600-273=327^{\circ} \mathrm{C}\)
\(
\begin{aligned}
\mathrm{PV} & =\mathrm{nRT} \\
\therefore \mathrm{T} & =\frac{\mathrm{PV}}{\mathrm{nR}}=\frac{4.926 \times 20}{12 \times 0.0821} \\
\mathrm{~T} & =600 \mathrm{~K}
\end{aligned}
\)
Temp. in \({ }^{\circ} \mathrm{C}=600-273=327^{\circ} \mathrm{C}\)
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