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MHT CET · Chemistry · Solid State

Find the radius of an atom in fcc unit cell having edge length \(405 \mathrm{pm}\).

  1. A \(202.5 \mathrm{pm}\)
  2. B \(175.3 \mathrm{pm}\)
  3. C \(143.2 \mathrm{pm}\)
  4. D \(181.0 \mathrm{pm}\)
Verified Solution

Answer & Solution

Correct Answer

(C) \(143.2 \mathrm{pm}\)

Step-by-step Solution

Detailed explanation

For fcc crystal structure, \(r=\frac{\sqrt{2}}{4} a\)
\(\therefore \quad \mathrm{r}=\frac{1.414 \times 405}{4}=143.2 \mathrm{pm}\)