MHT CET · Chemistry · Chemical Kinetics
Find the percentage of unreacted reactant for zero order reaction in 90 second having rate constant \(1 \mathrm{~mol} \mathrm{dm}^{-3} \mathrm{~s}^{-1}\).
- A \(5 \%\)
- B \(10 \%\)
- C \(15 \%\)
- D \(20 \%\)
Answer & Solution
Correct Answer
(B) \(10 \%\)
Step-by-step Solution
Detailed explanation
The rate constant of zero order reaction is given by equation
\(\mathrm{k}=\frac{[\mathrm{A}]_0-[\mathrm{A}]_{\mathrm{t}}}{\mathrm{t}}\)
\(\operatorname{Let}[\mathrm{A}]_0=100 \%\)
\(\begin{array}{ll}
\therefore & 1 \mathrm{~mol} \mathrm{dm}^{-3} \mathrm{~s}^{-1}=\frac{100-[\mathrm{A}]_{\mathrm{t}}}{90} \\
\therefore & {[\mathrm{~A}]_{\mathrm{t}}=100-90=10 \%}
\end{array}\)
\(\mathrm{k}=\frac{[\mathrm{A}]_0-[\mathrm{A}]_{\mathrm{t}}}{\mathrm{t}}\)
\(\operatorname{Let}[\mathrm{A}]_0=100 \%\)
\(\begin{array}{ll}
\therefore & 1 \mathrm{~mol} \mathrm{dm}^{-3} \mathrm{~s}^{-1}=\frac{100-[\mathrm{A}]_{\mathrm{t}}}{90} \\
\therefore & {[\mathrm{~A}]_{\mathrm{t}}=100-90=10 \%}
\end{array}\)
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