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MHT CET · Chemistry · Electrochemistry

Find the number of faradays of electricity required to produce \(45 \mathrm{~g}\) of \(\mathrm{Al}\) from molten \(\mathrm{Al}_2 \mathrm{O}_3\).

  1. A \(1 \mathrm{~F}\)
  2. B \(3 \mathrm{~F}\)
  3. C \(5\mathrm{~F}\)
  4. D \(7 \mathrm{~F}\)
Verified Solution

Answer & Solution

Correct Answer

(C) \(5\mathrm{~F}\)

Step-by-step Solution

Detailed explanation

\(
\mathrm{Al}^{3+}+3 \mathrm{e}^{-} \longrightarrow \mathrm{Al}
\)
The equation shows that 3 moles of electrons are required to produce 1 mole of \(\mathrm{Al}\) (i.e., \(27 \mathrm{~g}\) of \(\mathrm{Al}\) ).
\(\therefore3 \mathrm{~F}\) of electricity is required to produce \(27 \mathrm{~g}\) of \(\mathrm{Al}\) from molten \(\mathrm{Al}_2 \mathrm{O}_3\).
\(\therefore\) Faradays of electricity required to produce \(45 \mathrm{~g}\) of \(\mathrm{Al}=\frac{3}{27} \times 45=5 \mathrm{~F}\)