MHT CET · Chemistry · Some Basic Concepts of Chemistry
Find the mass of potassium chloride required to liberate \(5.6 \mathrm{~dm}^3\) of oxygen gas at STP ? (molar mass of \(\mathrm{KClO}_3=122.5 \mathrm{~g} / \mathrm{mol}\) )
- A 12.25 g
- B 15.32 g
- C 20.40 g
- D 49.00 g
Answer & Solution
Correct Answer
(C) 20.40 g
Step-by-step Solution
Detailed explanation
\( \mathrm{Moles~of~O}_2 = \frac{5.6 \mathrm{~dm}^3}{22.4 \mathrm{~dm}^3/\mathrm{mol}} = 0.25 \mathrm{~mol} \) \( 2 \mathrm{KClO}_3 \rightarrow 2 \mathrm{KCl} + 3 \mathrm{O}_2 \)
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