MHT CET · Chemistry · Thermodynamics (C)
Find the average rate of formation \(\mathrm{O}_{2(\mathrm{~g})}\) in the following reaction.
\(2 \mathrm{NO}_{2(\mathrm{~g})} \rightarrow 2 \mathrm{NO}_{(\mathrm{g})}+\mathrm{O}_{2(\mathrm{~g})} {\left[-\frac{\Delta[\mathrm{NO}]}{\Delta \mathrm{t}}\right]}\)\(=\mathrm{x} \mathrm{moldm}^{-3} \mathrm{~s}^{-1}\)
- A \(\frac{x}{2} \mathrm{~mol} \mathrm{dm}^{-3} \mathrm{~s}^{-1}\)
- B \(\mathrm{x} \mathrm{mol} \mathrm{dm}^{-3} \mathrm{~s}^{-1}\)
- C \(2 \times \mathrm{mol} \mathrm{dm}^{-3} \mathrm{~s}^{-1}\)
- D \(4 \times \mathrm{mol} \mathrm{dm}^{-3} \mathrm{~s}^{-1}\)
Answer & Solution
Correct Answer
(A) \(\frac{x}{2} \mathrm{~mol} \mathrm{dm}^{-3} \mathrm{~s}^{-1}\)
Step-by-step Solution
Detailed explanation
Average rate of reaction
\(=-\frac{1}{2} \frac{\Delta\left[\mathrm{NO}_2\right]}{\Delta \mathrm{t}}=\frac{1}{2} \frac{\Delta\left[\mathrm{NO}_2\right]}{\Delta \mathrm{t}}=\frac{\Delta\left[\mathrm{O}_2\right]}{\Delta \mathrm{t}}\)
Rate of formation of \(\mathrm{O}_2=\frac{\Delta\left[\mathrm{O}_2\right]}{\Delta \mathrm{t}}\)
\(\begin{aligned}
& =\frac{1}{2} \frac{-\Delta\left[\mathrm{NO}_2\right]}{\Delta \mathrm{t}} \\
& =\frac{1}{2} \times \mathrm{x}=\frac{\mathrm{x}}{2} \mathrm{~mol} \mathrm{dm}^{-3} \mathrm{~s}^{-1}
\end{aligned}\)
\(=-\frac{1}{2} \frac{\Delta\left[\mathrm{NO}_2\right]}{\Delta \mathrm{t}}=\frac{1}{2} \frac{\Delta\left[\mathrm{NO}_2\right]}{\Delta \mathrm{t}}=\frac{\Delta\left[\mathrm{O}_2\right]}{\Delta \mathrm{t}}\)
Rate of formation of \(\mathrm{O}_2=\frac{\Delta\left[\mathrm{O}_2\right]}{\Delta \mathrm{t}}\)
\(\begin{aligned}
& =\frac{1}{2} \frac{-\Delta\left[\mathrm{NO}_2\right]}{\Delta \mathrm{t}} \\
& =\frac{1}{2} \times \mathrm{x}=\frac{\mathrm{x}}{2} \mathrm{~mol} \mathrm{dm}^{-3} \mathrm{~s}^{-1}
\end{aligned}\)
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