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MHT CET · Chemistry · Solutions

Find the amount of solute in solution obtained by dissolving it in \(2.5 \mathrm{dm}^3\) water that generates osmotic pressure \(0.245 \mathrm{~atm}\). at \(300 \mathrm{~K}\) ?
(Molar mass of solute \(=58 \mathrm{~g} \mathrm{~mol}^{-1} \mathrm{R}=0.0821 \mathrm{dm}^3 \mathrm{~atm} \mathrm{~K}^{-1} \mathrm{~mol}^{-1}\) )

  1. A 1.75 gram
  2. B 1.0 gram
  3. C 0.72 gram
  4. D 1.44 gram
Verified Solution

Answer & Solution

Correct Answer

(D) 1.44 gram

Step-by-step Solution

Detailed explanation

\(\begin{aligned} & \pi=C R T \\ & 0.245=\frac{W}{58} \times \frac{1}{2.5} \times 0.0821 \times 300 \\ & W=1.44 \mathrm{~g}\end{aligned}\)
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