MHT CET · Chemistry · Thermodynamics (C)
Enthalpy of fusion and enthalpy of vaporization for water respectively are \(6 \cdot 01 \mathrm{~kJ} \mathrm{~mol}^{-1}\) and \(45 \cdot 07 \mathrm{~kJ} \mathrm{~mol}^{-1}\) at \(0^{\circ} \mathrm{C}\) what is enthalpy of sublimation at \(0^{\circ} \mathrm{C}\) ?
- A \(27 \cdot 50 \mathrm{~kJ} \mathrm{~mol}^{-1}\)
- B \(48 \cdot 07 \mathrm{~kJ} \mathrm{~mol}^{-1}\)
- C \(51 \cdot 08 \mathrm{~kJ} \mathrm{~mol}^{-1}\)
- D \(39 \cdot 06 \mathrm{~kJ} \mathrm{~mol}^{-1}\)
Answer & Solution
Correct Answer
(C) \(51 \cdot 08 \mathrm{~kJ} \mathrm{~mol}^{-1}\)
Step-by-step Solution
Detailed explanation
\(\Delta_{\text {fus }} \mathrm{H}=6.01 \mathrm{~kJ} \mathrm{~mol}^{-1}\)
\(\Delta_{\mathrm{vep}} \mathrm{H}=45.07 \mathrm{~kJ} \mathrm{~mol}^{-1}, \Delta_{\mathrm{eub}} \mathrm{H}=?\)
For sublimation at \(0^{\circ} \mathrm{C}\),
\(\mathrm{H}_{2} \mathrm{O}_{(t)} \stackrel{\Delta H_{1} \rightarrow}{\longrightarrow} \mathrm{H}_{2} \mathrm{O}_{(\lambda)} \stackrel{\Delta \mathrm{H}_{2}}{\longrightarrow} \mathrm{H}_{2} \mathrm{O}_{(\varepsilon)}\)
\(\Delta_{\text {sub }} H=6.01+45.07=51.08 \mathrm{~kJ} \mathrm{~mol}^{-1}\)
\(\Delta_{\mathrm{vep}} \mathrm{H}=45.07 \mathrm{~kJ} \mathrm{~mol}^{-1}, \Delta_{\mathrm{eub}} \mathrm{H}=?\)
For sublimation at \(0^{\circ} \mathrm{C}\),
\(\mathrm{H}_{2} \mathrm{O}_{(t)} \stackrel{\Delta H_{1} \rightarrow}{\longrightarrow} \mathrm{H}_{2} \mathrm{O}_{(\lambda)} \stackrel{\Delta \mathrm{H}_{2}}{\longrightarrow} \mathrm{H}_{2} \mathrm{O}_{(\varepsilon)}\)
\(\Delta_{\text {sub }} H=6.01+45.07=51.08 \mathrm{~kJ} \mathrm{~mol}^{-1}\)
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