MHT CET · Chemistry · Solid State
Edge length of unit cell of BCC structure is \(352 \mathrm{pm}\). What is radius of the atoms?
- A 176.3 pm
- B 304.8 pm
- C 152.4 pm
- D 252.4 pm
Answer & Solution
Correct Answer
(C) 152.4 pm
Step-by-step Solution
Detailed explanation
For BCC unit cell,
\(
\begin{aligned}
& 4 \mathrm{r}=\sqrt{3} \mathrm{a} \\
& \mathrm{r}=\frac{\sqrt{3} \mathrm{a}}{4}=\frac{1.732 \times 352}{4}=152.4 \mathrm{pm}
\end{aligned}
\)
\(
\begin{aligned}
& 4 \mathrm{r}=\sqrt{3} \mathrm{a} \\
& \mathrm{r}=\frac{\sqrt{3} \mathrm{a}}{4}=\frac{1.732 \times 352}{4}=152.4 \mathrm{pm}
\end{aligned}
\)
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