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MHT CET · Chemistry · Electrochemistry

During the electrolysis of fused \(\mathrm{NaCl}\), the product obtained at anode is

  1. A \(\mathrm{Na}_{(\mathrm{s})}\)
  2. B \(\mathrm{Cl}_{2(\mathrm{~g})}\)
  3. C \(\mathrm{O}_{2(\mathrm{~g})}\)
  4. D \(\mathrm{Na}_{(l)}\)
Verified Solution

Answer & Solution

Correct Answer

(B) \(\mathrm{Cl}_{2(\mathrm{~g})}\)

Step-by-step Solution

Detailed explanation

Anode: The electrode of an electrochemical cell at which oxidation occurs.
Cathode: The electrode of an electrochemical cell at which reduction occurs.
Electrolysis of molten \(\mathrm{NaCl}\) or fused \(\mathrm{NaCl}\)
Sodium ions migrate to cathode, where electron enter, the melt is reduced to sodium metal
\(
\mathrm{Na}^{+}+\mathrm{e}^{-} \longrightarrow \mathrm{Cl}_2+\mathrm{e}^{-}
\)
Chlorine ions migrate to anode. They give up their electrons to the anode
and are oxidized to chlorine gas:
\(
\mathrm{Cl}^{-} \longrightarrow \frac{1}{2} \mathrm{Cl}_2+\mathrm{e}^{-}
\)
Overall reaction
\(
2 \mathrm{NaCl} \longrightarrow 2 \mathrm{Na}(\mathrm{s})+\mathrm{Cl}_2 \text { (g) }
\)