MHT CET · Chemistry · Chemical Kinetics
Consider the reaction \(2 \mathrm{~A}+2 \mathrm{~B} \rightarrow \mathrm{C}+2 \mathrm{D}\). If the concentration of \(\mathrm{A}\) is doubled at constant \(\mathrm{B}\), the rate increases by a factor 4 . If the concentration of \(\mathrm{B}\) is doubled at constant \(A\), rate is doubled. What is the rate law?
- A \(r=k[A]^{2}[B]^{2}\)
- B \(r=k[A]^{4}[B]^{2}\)
- C \(r=k[A][B]^{2}\)
- D \(r=k[A]^{2}[B]\)
Answer & Solution
Correct Answer
(D) \(r=k[A]^{2}[B]\)
Step-by-step Solution
Detailed explanation
\(\mathrm{A}+\mathrm{B}_{2} \longrightarrow \mathrm{AB}+\mathrm{B}\)
Given Rate \(\propto[\mathrm{A}]\) and not on \([\mathrm{B}]\)
Rate depends on concentration of reactants.
Rate \(=\mathrm{k}[\mathrm{A}]\)
Given Rate \(\propto[\mathrm{A}]\) and not on \([\mathrm{B}]\)
Rate depends on concentration of reactants.
Rate \(=\mathrm{k}[\mathrm{A}]\)
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