MHT CET · Chemistry · Thermodynamics (C)
Calculate work done if 1 mole of an ideal gas compressed isothermally and reversibly from \(12 \mathrm{dm}^3\) to \(6 \mathrm{dm}^3\) at 300 K.
\(\left[\mathrm{R}=8 \cdot 314 \mathrm{JK}^{-1} \mathrm{~mol}^{-1}\right]\)
- A 1.729 kJ
- B 3.458 kJ
- C 5.187 kJ
- D 6.916 kJ
Answer & Solution
Correct Answer
(A) 1.729 kJ
Step-by-step Solution
Detailed explanation
\(W = -nRT \ln \left( \frac{V_2}{V_1} \right)\) \(W = -(1 \mathrm{mol}) (8.314 \mathrm{J K^{-1} mol^{-1}}) (300 \mathrm{K}) \ln \left( \frac{6 \mathrm{dm}^3}{12 \mathrm{dm}^3} \right)\)
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