MHT CET · Chemistry · Structure of Atom
Calculate velocity of an electron having de Broglie's wavelength 58 nm and mass \(9.1 \times 10^{-31} \mathrm{~kg} ?\left[\mathrm{~h}=6.63 \times 10^{-34} \mathrm{Js}\right]\)
- A \(2.12 \times 10^5 \mathrm{~ms}^{-1}\)
- B \(1.68 \times 10^5 \mathrm{~ms}^{-1}\)
- C \(1.26 \times 10^4 \mathrm{~ms}^{-1}\)
- D \(4.09 \times 10^4 \mathrm{~ms}^{-1}\)
Answer & Solution
Correct Answer
(C) \(1.26 \times 10^4 \mathrm{~ms}^{-1}\)
Step-by-step Solution
Detailed explanation
\( v = \frac{h}{m\lambda} = \frac{6.63 \times 10^{-34}}{(9.1 \times 10^{-31})(58 \times 10^{-9})} = 1.26 \times 10^4 \mathrm{~ms}^{-1} \)
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