MHT CET · Chemistry · Thermodynamics (C)
Calculate the work done in the following reaction at \(300 \mathrm{~K}\) and at constant pressure.
\(\left(\mathrm{R}=8.314 \mathrm{~J} \mathrm{~K}^{-1} \mathrm{~mol}^{-1}\right) 4 \mathrm{HCl}_{(\mathrm{g})}+\) \(\mathrm{O}_{2(\mathrm{~g})} \rightarrow 2 \mathrm{Cl}_{2(\mathrm{~g})}+2 \mathrm{H}_2 \mathrm{O}_{(\mathrm{g})}\)
- A \(-7482 \mathrm{~J}\)
- B \(-4988 \mathrm{~J}\)
- C \(2494 \mathrm{~J}\)
- D \(3200 \mathrm{~J}\)
Answer & Solution
Correct Answer
(C) \(2494 \mathrm{~J}\)
Step-by-step Solution
Detailed explanation
\(\begin{aligned} \mathrm{W} & =-\Delta \mathrm{n}_{\mathrm{g}} \mathrm{RT} \\ & =-(4-5) \times 8.314 \times 300 \\ & =1 \times 8.314 \times 300 \\ & =2494.2 \mathrm{~J}\end{aligned}\)
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