MHT CET · Chemistry · Thermodynamics (C)
Calculate the work done during compression of 2 mol of an ideal gas from a volume of to 10 at 300 K against a pressure of 100 KPa.
- A - 99 kJ
- B +99 kJ
- C +22.98 kJ
- D -22.98 kJ
Answer & Solution
Correct Answer
(B) +99 kJ
Step-by-step Solution
Detailed explanation
\(W=-P_{\text {ext }} \Delta V, \Delta V=\left(0.01 m^3-1 m^3\right)\)\(=-0.99 m^3\)
\(=-100~ k P a(-0.99) m^3\)
\(=99~ kJ\)
\(=-100~ k P a(-0.99) m^3\)
\(=99~ kJ\)
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