MHT CET · Chemistry · Structure of Atom
Calculate the wavenumber of photon emitted during transition from the orbit of \(n=3\) to \(n=2\) in hydrogen atom. \(\left(\mathrm{R}_{\mathrm{H}}=109677 \mathrm{~cm}^{-1}\right)\)
- A \(15354.8 \mathrm{~cm}^{-1}\)
- B \(82257.8 \mathrm{~cm}^{-1}\)
- C \(30515.4 \mathrm{~cm}^{-1}\)
- D \(41128.5 \mathrm{~cm}^{-1}\)
Answer & Solution
Correct Answer
(A) \(15354.8 \mathrm{~cm}^{-1}\)
Step-by-step Solution
Detailed explanation
\(\bar{v}=109677\left[\frac{1}{n_f^2}-\frac{1}{n_i^2}\right] \mathrm{cm}^{-1}\)
\(=109677\left[\frac{1}{2^2}-\frac{1}{3^2}\right] \mathrm{cm}^{-1}\)
\(=109677\left[\frac{1}{4}-\frac{1}{9}\right] \mathrm{cm}^{-1}\)
\(=109677\left[\frac{9-4}{9 \times 4}\right] \mathrm{cm}^{-1}\)
\(=109677\left[\frac{5}{36}\right] \mathrm{cm}^{-1}\)
\(=15232.9 \mathrm{~cm}^{-1}\)
\(=109677\left[\frac{1}{2^2}-\frac{1}{3^2}\right] \mathrm{cm}^{-1}\)
\(=109677\left[\frac{1}{4}-\frac{1}{9}\right] \mathrm{cm}^{-1}\)
\(=109677\left[\frac{9-4}{9 \times 4}\right] \mathrm{cm}^{-1}\)
\(=109677\left[\frac{5}{36}\right] \mathrm{cm}^{-1}\)
\(=15232.9 \mathrm{~cm}^{-1}\)
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