MHT CET · Chemistry · Structure of Atom
Calculate the wave number of photon emitted during transition from the orbit \(\mathrm{n}=2\) to \(\mathrm{n}=1\) in hydrogen atom \(\left(\mathrm{R}_{\mathrm{H}}=109677 \mathrm{~cm}^{-1}\right)\)
- A \(72740 \mathrm{~cm}^{-1}\)
- B \(92820 \mathrm{~cm}^{-1}\)
- C \(82258 \mathrm{~cm}^{-1}\)
- D \(83560 \mathrm{~cm}^{-1}\)
Answer & Solution
Correct Answer
(C) \(82258 \mathrm{~cm}^{-1}\)
Step-by-step Solution
Detailed explanation
\(\begin{aligned} & \overline{\mathrm{V}}=\mathrm{R}_{\mathrm{H}}\left(\frac{1}{\mathrm{n}_1^2}-\frac{1}{\mathrm{n}_2^2}\right) \\ & =109677\left(\frac{1}{1^2}-\frac{1}{2^2}\right) \\ & =82,257.75 \mathrm{~cm}^{-1}\end{aligned}\)
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