MHT CET · Chemistry · Solid State
Calculate the volume of unit cell if an element having molar mass \(56 \mathrm{~g} \mathrm{~mol}^{-1}\) that forms bcc unit cells.
\(
\left[\rho . \mathrm{N}_{\mathrm{A}}=4: 8 \times 10^{24} \mathrm{~g} \mathrm{~cm}^{-3} \mathrm{~mol}^{-1}\right]
\)
- A \(1.17 \times 10^{-23} \mathrm{~cm}^3\)
- B \(4.79 \times 10^{-23} \mathrm{~cm}^3\)
- C \(3.31 \times 10^{-23} \mathrm{~cm}^3\)
- D \(2.33 \times 10^{-23} \mathrm{~cm}^3\)
Answer & Solution
Correct Answer
(D) \(2.33 \times 10^{-23} \mathrm{~cm}^3\)
Step-by-step Solution
Detailed explanation
\(\text {Density of unit cell }=\rho=\frac{M n}{a^3 N_A} \)
\( \text {Volume of unit cell }\left(a^3\right)=\frac{M n}{\rho N_A} \)
\( =\frac{56 \mathrm{~g} \mathrm{~mol}^{-1} \times 2}{4.8 \times 10^{24} \mathrm{~g} \mathrm{~cm}^{-3} \mathrm{~mol}^{-1}} \)
\( =2.33 \times 10^{-23} \mathrm{~cm}^3\)
\( \text {Volume of unit cell }\left(a^3\right)=\frac{M n}{\rho N_A} \)
\( =\frac{56 \mathrm{~g} \mathrm{~mol}^{-1} \times 2}{4.8 \times 10^{24} \mathrm{~g} \mathrm{~cm}^{-3} \mathrm{~mol}^{-1}} \)
\( =2.33 \times 10^{-23} \mathrm{~cm}^3\)
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