MHT CET · Chemistry · Solid State
Calculate the total volume occupied by all atoms in simple cubic unit cell if radius of atom is \(3 \times 10^{-8} \mathrm{~cm}\) :
- A \(1.13 \times 10^{-22} \mathrm{~cm}^3\)
- B \(2.25 \times 10^{-22} \mathrm{~cm}^3\)
- C \(3.15 \times 10^{-22} \mathrm{~cm}^3\)
- D \(4.37 \times 10^{-22} \mathrm{~cm}^3\)
Answer & Solution
Correct Answer
(A) \(1.13 \times 10^{-22} \mathrm{~cm}^3\)
Step-by-step Solution
Detailed explanation
For simple cubic unit cell, \(\mathrm{n}=1\)
Total volume occupied by atoms in SCC
\(=\mathrm{n} \times \frac{4}{3} \times \pi \mathrm{r}^3\)
\(=1 \times \frac{4}{3} \times \frac{22}{7} \times\left(3 \times 10^{-8}\right)^3=\) \(1.13 \times 10^{-22} \mathrm{~cm}^3\)
Total volume occupied by atoms in SCC
\(=\mathrm{n} \times \frac{4}{3} \times \pi \mathrm{r}^3\)
\(=1 \times \frac{4}{3} \times \frac{22}{7} \times\left(3 \times 10^{-8}\right)^3=\) \(1.13 \times 10^{-22} \mathrm{~cm}^3\)
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