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MHT CET · Chemistry · Solid State

Calculate the total number of tetrahedral and octahedral voids in 0.4 mol compound having such voids in it.

  1. A \(2.4088 \times 10^{23}\)
  2. B \(7.2264 \times 10^{23}\)
  3. C \(4.8176 \times 10^{23}\)
  4. D \(9.6352 \times 10^{23}\)
Verified Solution

Answer & Solution

Correct Answer

(B) \(7.2264 \times 10^{23}\)

Step-by-step Solution

Detailed explanation

Number of atoms \(N = 0.4 \times 6.022 \times 10^{23} = 2.4088 \times 10^{23}\) Total voids \( = N_{octahedral} + N_{tetrahedral} = N + 2N = 3N \)