MHT CET · Chemistry · Thermodynamics (C)
Calculate the standard enthalpy change for synthesis of ammonia gas from following data
i. \(2 \mathrm{H}_{2(\mathrm{~g})}+\mathrm{N}_{2(\mathrm{~g})} \longrightarrow \mathrm{N}_2 \mathrm{H}_{4(\mathrm{~g})} ; \quad \Delta_{\mathrm{r}} \mathrm{H}_1^0=95.4 \mathrm{~kJ}\)
ii. \(\mathrm{N}_2 \mathrm{H}_{4(\mathrm{~g})}+\mathrm{H}_{2(\mathrm{~g})} \longrightarrow 2 \mathrm{NH}_{3(\mathrm{~g})} ; \quad \Delta_{\mathrm{r}} \mathrm{H}_2^0=-187 \cdot 6 \mathrm{~kJ}\)
- A \(-92 \cdot 2 \mathrm{~kJ}\)
- B \(-46 \cdot 1 \mathrm{~kJ}\)
- C \(-138 \cdot 3 \mathrm{~kJ}\)
- D \(-283 \cdot 2 \mathrm{~kJ}\)
Answer & Solution
Correct Answer
(A) \(-92 \cdot 2 \mathrm{~kJ}\)
Step-by-step Solution
Detailed explanation
\( \Delta_{\mathrm{r}} \mathrm{H}^0 = \Delta_{\mathrm{r}} \mathrm{H}_1^0 + \Delta_{\mathrm{r}} \mathrm{H}_2^0 \) \( \Delta_{\mathrm{r}} \mathrm{H}^0 = 95.4 \mathrm{~kJ} + (-187.6 \mathrm{~kJ}) \)
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