MHT CET · Chemistry · Ionic Equilibrium
Calculate the solubility product of sparingly soluble salt BA at \(25^{\circ} \mathrm{C}\) if its solubility is \(7.2 \times 10^{-7} \mathrm{~mol} \mathrm{dm}^{-3}\) at same temperature.
- A \(4.810 \times 10^{-13}\)
- B \(5.184 \times 10^{-13}\)
- C \(6.454 \times 10^{-13}\)
- D \(5.925 \times 10^{-13}\)
Answer & Solution
Correct Answer
(B) \(5.184 \times 10^{-13}\)
Step-by-step Solution
Detailed explanation
\(\mathrm{BA}_{(\mathrm{s})} \rightleftharpoons \mathrm{B}_{(\mathrm{aq})}^{+}+\mathrm{A}_{(\mathrm{aq})}^{-} \)
\( x=1, \mathrm{y}=1 \)
\( \mathrm{K}_{\mathrm{sp}}=x^x \mathrm{y}^{\mathrm{y}} \mathrm{S}^{x+\mathrm{y}}=(1)^1(1)^1 \mathrm{~S}^{1+1}=\mathrm{S}^2 \)
\( \therefore \mathrm{K}_{\mathrm{sp}}=\left(7.2 \times 10^{-7}\right)^2=5.184 \times 10^{-13}\)
\( x=1, \mathrm{y}=1 \)
\( \mathrm{K}_{\mathrm{sp}}=x^x \mathrm{y}^{\mathrm{y}} \mathrm{S}^{x+\mathrm{y}}=(1)^1(1)^1 \mathrm{~S}^{1+1}=\mathrm{S}^2 \)
\( \therefore \mathrm{K}_{\mathrm{sp}}=\left(7.2 \times 10^{-7}\right)^2=5.184 \times 10^{-13}\)
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