MHT CET · Chemistry · Ionic Equilibrium
Calculate the solubility product of sparingly soluble salt BA at \(27^{\circ} \mathrm{C}\) if its solubility is \(1.8 \times 10^{-5} \mathrm{~mol} \mathrm{dm}^{-3}\) at same temperature.
- A \(3.24 \times 10^{-10}\)
- B \(2.44 \times 10^{-10}\)
- C \(1.64 \times 10^{-10}\)
- D \(4.00 \times 10^{-10}\)
Answer & Solution
Correct Answer
(A) \(3.24 \times 10^{-10}\)
Step-by-step Solution
Detailed explanation
\(\begin{aligned} & \mathrm{BA}_{(\mathrm{s})} \rightleftharpoons \mathrm{B}_{(\mathrm{aq})}^{+}+\mathrm{A}_{(\mathrm{aq})}^{-} \\ & \begin{aligned} \mathrm{K}_{\mathrm{sp}} & =\mathrm{S}^2=\left(1.8 \times 10^{-5} \mathrm{~mol} \mathrm{dm}^{-3}\right)^2 \\ & =3.24 \times 10^{-10} \cdot \mathrm{~mol}^2 \mathrm{dm}^{-6}\end{aligned}\end{aligned}\)
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