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MHT CET · Chemistry · Solutions

Calculate the solubility of gas in solvent at \(25^{\circ} \mathrm{C}\) and 0.8 atm if Henry's law constant for solvent is \(6.8 \times 10^{-4} \mathrm{~mol~} \mathrm{dm}^{-3} \mathrm{~atm}^{-1}\).

  1. A \(5.88 \times 10^{-4} \mathrm{M}\)
  2. B \(6.12 \times 10^{-4} \mathrm{M}\)
  3. C \(5.44 \times 10^{-4} \mathrm{M}\)
  4. D \(6.48 \times 10^{-4} \mathrm{M}\)
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Correct Answer

(C) \(5.44 \times 10^{-4} \mathrm{M}\)

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