MHT CET · Chemistry · Solutions
Calculate the relative lowering of vapour pressure if the vapour pressure of benzene and vapour pressure of solution of non-volatile solute in benzene are \(640 \mathrm{mmHg}\) and \(590 \mathrm{mmHg}\) respectively at same temperature.
- A \(0.078\)
- B \(0.175\)
- C \(0.061\)
- D \(0.092\)
Answer & Solution
Correct Answer
(A) \(0.078\)
Step-by-step Solution
Detailed explanation
Relative lowering of vapour pressure
\(
\begin{aligned}
& =\frac{\Delta \mathrm{P}}{\mathrm{P}_1^0}=\frac{\mathrm{P}_1^0-\mathrm{P}_1}{\mathrm{P}_1^0} \\
& =\frac{640-590}{640}=0.078
\end{aligned}
\)
\(
\begin{aligned}
& =\frac{\Delta \mathrm{P}}{\mathrm{P}_1^0}=\frac{\mathrm{P}_1^0-\mathrm{P}_1}{\mathrm{P}_1^0} \\
& =\frac{640-590}{640}=0.078
\end{aligned}
\)
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