MHT CET · Chemistry · Chemical Kinetics
Calculate the rate constant of first order reaction if half life of reaction is 40 minutes.
- A \(1.733 \times 10^{-2}\) minute \(^{-1}\)
- B \(1.951 \times 10^{-2}\) minute \(^{-1}\)
- C \(1.423 \times 10^{-2}\) minute \(^{-1}\)
- D \(1.256 \times 10^{-2}\) minute \(^{-1}\)
Answer & Solution
Correct Answer
(A) \(1.733 \times 10^{-2}\) minute \(^{-1}\)
Step-by-step Solution
Detailed explanation
For a first order reaction, \(k=\frac{0.693}{t_{1 / 2}}\)
\(
\mathrm{k}=\frac{0.693}{40}=1.733 \times 10^{-2} \text { minute }^{-1}
\)
\(
\mathrm{k}=\frac{0.693}{40}=1.733 \times 10^{-2} \text { minute }^{-1}
\)
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