ExamBro
ExamBro
MHT CET · Chemistry · Chemical Kinetics

Calculate the rate constant of first order reaction if half life of reaction is 40 minutes.

  1. A \(1.733 \times 10^{-2}\) minute \(^{-1}\)
  2. B \(1.951 \times 10^{-2}\) minute \(^{-1}\)
  3. C \(1.423 \times 10^{-2}\) minute \(^{-1}\)
  4. D \(1.256 \times 10^{-2}\) minute \(^{-1}\)
Verified Solution

Answer & Solution

Correct Answer

(A) \(1.733 \times 10^{-2}\) minute \(^{-1}\)

Step-by-step Solution

Detailed explanation

For a first order reaction, \(k=\frac{0.693}{t_{1 / 2}}\)
\(
\mathrm{k}=\frac{0.693}{40}=1.733 \times 10^{-2} \text { minute }^{-1}
\)