MHT CET · Chemistry · Chemical Kinetics
Calculate the rate constant for the first order reaction, \(\mathrm{A} \rightarrow \mathrm{B}\) if the rate of reaction is \(5.4 \times 10^{-6} \mathrm{~mol} \mathrm{dm}^{-3} \mathrm{~s}^{-1}\) and \([\mathrm{A}]=0.3 \mathrm{M}\).
- A \(1.8 \times 10^{-5} \mathrm{~s}^{-1}\)
- B \(1.5 \times 10^{-5} \mathrm{~s}^{-1}\)
- C \(2.1 \times 10^{-5} \mathrm{~s}^{-1}\)
- D \(2.4 \times 10^{-5} \mathrm{~s}^{-1}\)
Answer & Solution
Correct Answer
(A) \(1.8 \times 10^{-5} \mathrm{~s}^{-1}\)
Step-by-step Solution
Detailed explanation
For the first order reaction, \(\mathrm{A} \longrightarrow \mathrm{B}\), Rate \(=\mathrm{k}[\mathrm{A}]\)
\(\begin{aligned}
\therefore \quad \mathrm{k} & =\frac{\text { Rate }}{[\mathrm{A}]}=\frac{5.4 \times 10^{-6} \mathrm{~mol} \mathrm{dm}^{-3} \mathrm{~s}^{-1}}{0.3 \mathrm{~mol} \mathrm{dm}^{-3}} \\
& =1.8 \times 10^{-5} \mathrm{~s}^{-1}
\end{aligned}\)
\(\begin{aligned}
\therefore \quad \mathrm{k} & =\frac{\text { Rate }}{[\mathrm{A}]}=\frac{5.4 \times 10^{-6} \mathrm{~mol} \mathrm{dm}^{-3} \mathrm{~s}^{-1}}{0.3 \mathrm{~mol} \mathrm{dm}^{-3}} \\
& =1.8 \times 10^{-5} \mathrm{~s}^{-1}
\end{aligned}\)
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