MHT CET · Chemistry · Structure of Atom
Calculate the radius of first orbit of \(\mathrm{Li}^{++}\).
- A 70.53 pm
- B 158.7 pm
- C 17.63 pm
- D 282.13 pm
Answer & Solution
Correct Answer
(C) 17.63 pm
Step-by-step Solution
Detailed explanation
\(\mathrm{r}_{\mathrm{n}}=\frac{52.9\left(\mathrm{n}^2\right)}{\mathrm{Z}} \mathrm{pm}\)
For \(\mathrm{Li}^{++}, \mathrm{Z}=3\)
First orbit, n = 1
\(\mathrm{r}_{\mathrm{n}}=\frac{52.9\left(\mathrm{n}^2\right)}{\mathrm{Z}} \cdot \mathrm{pm}=\frac{52.9(1)^2}{3}=17.63 \mathrm{pm}\)
For \(\mathrm{Li}^{++}, \mathrm{Z}=3\)
First orbit, n = 1
\(\mathrm{r}_{\mathrm{n}}=\frac{52.9\left(\mathrm{n}^2\right)}{\mathrm{Z}} \cdot \mathrm{pm}=\frac{52.9(1)^2}{3}=17.63 \mathrm{pm}\)
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