MHT CET · Chemistry · Electrochemistry
Calculate the quantity of electricity required to produced \(0.42 \mathrm{~g}\) \(\mathrm{Ag}\) at cathode during electrolysis of \(\mathrm{AgNO}_3\) solution. (molar mass Ag \(=108 \mathrm{~g} \mathrm{~mol}^{-1}\) )
- A \(965.0 \mathrm{C}\)
- B \(470.0 \mathrm{C}\)
- C \(257.1 \mathrm{C}\)
- D 375.3 C
Answer & Solution
Correct Answer
(D) 375.3 C
Step-by-step Solution
Detailed explanation
\(\mathrm{W}=\frac{\mathrm{EQ}}{\mathrm{F}}\)
\(0.42=\frac{108}{96500} \times Q\)
\(\mathrm{Q}=375.3 \mathrm{C}\)
\(0.42=\frac{108}{96500} \times Q\)
\(\mathrm{Q}=375.3 \mathrm{C}\)
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