MHT CET · Chemistry · Electrochemistry
Calculate the quantity of electricity required to liberate \(0.224 \mathrm{dm}^3\) of chlorine at STP during the electrolysis of fused sodium chloride?
- A 1090 C
- B 1930 C
- C 96500 C
- D 965 C
Answer & Solution
Correct Answer
(B) 1930 C
Step-by-step Solution
Detailed explanation
\( \text{Moles of } \mathrm{Cl}_2 = \frac{\text{Volume}}{\text{Molar volume at STP}} = \frac{0.224 \mathrm{dm}^3}{22.4 \mathrm{dm}^3/\mathrm{mol}} = 0.01 \mathrm{mol} \) \( \text{From } 2 \mathrm{Cl}^- \rightarrow \mathrm{Cl}_2 + 2 \mathrm{e}^-, \text{moles of } \mathrm{e}^- = 2 \times \text{moles of } \mathrm{Cl}_2 = 2 \times 0.01 \mathrm{mol} = 0.02 \mathrm{mol} \)
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