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MHT CET · Chemistry · Solutions

Calculate the pressure of gas if the solubility of gas in water at \(25^{\circ} \mathrm{C}\) is \(6.85 \times 10^4 \mathrm{~mol} \mathrm{dm}^{-3}\) (Henry's law constant is \(6.85 \times 10^4 \mathrm{~mol} \mathrm{dm}^{-3} \mathrm{bar}^{-1}\))

  1. A 0.853 bar
  2. B \(1.5 \mathrm{bar}\)
  3. C 0.5 bar
  4. D 1 bar
Verified Solution

Answer & Solution

Correct Answer

(D) 1 bar

Step-by-step Solution

Detailed explanation

We know
\(
\mathrm{S}=\mathrm{K}_{\mathrm{H}} \mathrm{P}
\)
In \(1 \mathrm{dm}^3\) or 1 lit moles of gas dissolved is \(6.85 \times 10^4\) \(\therefore \mathrm{p}=6.85 \times 10^4 / 6.85 \times 10^4=1.0\) bar.