MHT CET · Chemistry · Solutions
Calculate the pressure of gas if the solubility of gas in water at \(25^{\circ} \mathrm{C}\) is \(6.85 \times 10^4 \mathrm{~mol} \mathrm{dm}^{-3}\) (Henry's law constant is \(6.85 \times 10^4 \mathrm{~mol} \mathrm{dm}^{-3} \mathrm{bar}^{-1}\))
- A 0.853 bar
- B \(1.5 \mathrm{bar}\)
- C 0.5 bar
- D 1 bar
Answer & Solution
Correct Answer
(D) 1 bar
Step-by-step Solution
Detailed explanation
We know
\(
\mathrm{S}=\mathrm{K}_{\mathrm{H}} \mathrm{P}
\)
In \(1 \mathrm{dm}^3\) or 1 lit moles of gas dissolved is \(6.85 \times 10^4\) \(\therefore \mathrm{p}=6.85 \times 10^4 / 6.85 \times 10^4=1.0\) bar.
\(
\mathrm{S}=\mathrm{K}_{\mathrm{H}} \mathrm{P}
\)
In \(1 \mathrm{dm}^3\) or 1 lit moles of gas dissolved is \(6.85 \times 10^4\) \(\therefore \mathrm{p}=6.85 \times 10^4 / 6.85 \times 10^4=1.0\) bar.
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