MHT CET · Chemistry · Ionic Equilibrium
Calculate the pH of buffer solution containing 0.04 M NaF and \(0.02 \mathrm{MHF}\left[\mathrm{pK}_a=3 \cdot 142\right]\).
- A 4.5
- B 3.4
- C 2.6
- D 5.1
Answer & Solution
Correct Answer
(B) 3.4
Step-by-step Solution
Detailed explanation
0.04 M NaF and 0.02 M HF forms an acidic buffer.
\(\begin{aligned}
\mathrm{pH} & =\mathrm{pK}_{\mathrm{a}}+\log _{10} \frac{[\text { Salt }]}{[\text { Acid }]} \\
& =3.142+\log _{10} \frac{(0.04)}{(0.02)} \\
& =3.142+0.3010 \\
& =3.44 \approx 3.4
\end{aligned}\)
\(\begin{aligned}
\mathrm{pH} & =\mathrm{pK}_{\mathrm{a}}+\log _{10} \frac{[\text { Salt }]}{[\text { Acid }]} \\
& =3.142+\log _{10} \frac{(0.04)}{(0.02)} \\
& =3.142+0.3010 \\
& =3.44 \approx 3.4
\end{aligned}\)
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