MHT CET · Chemistry · Ionic Equilibrium
Calculate the \(\mathrm{pH}\) of \(1.36 \times 10^{-2} \mathrm{M}\) solution of perchloric acid.
- A \(1.43\)
- B \(1.86\)
- C \(2.43\)
- D \(2.86\)
Answer & Solution
Correct Answer
(B) \(1.86\)
Step-by-step Solution
Detailed explanation
Perchloric acid is a strong monobasic acid. Hence, \(\left[\mathrm{H}_3 \mathrm{O}^{+}\right]=1.36 \times 10^{-2} \mathrm{M}\)
\(\therefore \mathrm{pH} =-\log _{10}\left[\mathrm{H}_3 \mathrm{O}^{+}\right] \)
\( =-\log _{10}\left[1.36 \times 10^{-2}\right] \)
\( =-\log _{10} 1.36-\log _{10} 10^{-2} \)
\( =-\log _{10} 1.36+2 \)
\( =2-0.1335 \)
\( \therefore \mathrm{pH} =1.86\)
\(\therefore \mathrm{pH} =-\log _{10}\left[\mathrm{H}_3 \mathrm{O}^{+}\right] \)
\( =-\log _{10}\left[1.36 \times 10^{-2}\right] \)
\( =-\log _{10} 1.36-\log _{10} 10^{-2} \)
\( =-\log _{10} 1.36+2 \)
\( =2-0.1335 \)
\( \therefore \mathrm{pH} =1.86\)
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