MHT CET · Chemistry · Ionic Equilibrium
Calculate the \(\mathrm{pH}\) of \(0.01 \mathrm{M}\) strong dibasic acid.
- A \(5.5\)
- B \(2.5\)
- C \(2.0\)
- D \(1.7\)
Answer & Solution
Correct Answer
(D) \(1.7\)
Step-by-step Solution
Detailed explanation
\(\begin{aligned} & {\left[\mathrm{H}_3 \mathrm{O}^{+}\right]=2 \times \mathrm{c}=2 \times 0.01 \mathrm{M}=2 \times 10^{-2} \mathrm{M}} \\ & \mathrm{pH}=-\log _{10}\left[\mathrm{H}_3 \mathrm{O}^{+}\right] \\ & =-\log _{10}\left[2 \times 10^{-2}\right] \\ & =-\log _{10} 2-\log _{10} 10^{-2} \\ & =-\log _{10} 2+2 \\ & =2-0.3010 \\ & \mathrm{pH}=1.7 \\ & \end{aligned}\)
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