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MHT CET · Chemistry · Electrochemistry

Calculate the percentage dissociation of 0.05 M solution of weak electrolyte if its molar conductivity and molar conductivity at infinite dilution are respectively. \(3.3 \Omega^{-1} \mathrm{~cm}^2 \mathrm{~mol}^{-1}\) and \(132 \Omega^{-1} \mathrm{~cm}^2 \mathrm{~mol}^{-1}\).

  1. A \(4.0 \%\)
  2. B \(3.5 \%\)
  3. C \(2.5 \%\)
  4. D \(10.0 \%\)
Verified Solution

Answer & Solution

Correct Answer

(C) \(2.5 \%\)

Step-by-step Solution

Detailed explanation

\(\begin{aligned} & \text { Percentage dissociation }=\frac{\Lambda_c}{\Lambda_0} \times 100 \\ & =\frac{3.3 \Omega^{-1} \mathrm{~cm}^2 \mathrm{~mol}^{-1}}{132 \Omega^{-1} \mathrm{~cm}^2 \mathrm{~mol}^{-1}} \times 100=2.5 \%\end{aligned}\)