MHT CET · Chemistry · d and f Block Elements
Calculate the oxidation number of Cr in \(\mathrm{CrO}_4^{2-}\) ion and \(\mathrm{K}_2 \mathrm{Cr}_2 \mathrm{O}_7\) respectively.
- A +4 and +6
- B +3 and +2
- C +6 and +6
- D +8 and +2
Answer & Solution
Correct Answer
(C) +6 and +6
Step-by-step Solution
Detailed explanation
Let x be the oxidation number of Cr in \(\mathrm{CrO}_4^{2-}\)
\(\begin{array}{ll}
\therefore & x+4 \times(-2)=-2 \\
& x-8=-2 \\
\therefore & x=8-2=+6
\end{array}\)
Let \(y\) be the oxidation number of Cr in \(\mathrm{K}_2 \mathrm{Cr}_2 \mathrm{O}_7\)
\(\begin{array}{ll}
\therefore \quad & 2 \times(+1)+2(y)+7 \times(-2)=0 \\
& +2+2 y-14=0 \\
& 2 y=12 \\
\therefore \quad & y=+6
\end{array}\)
\(\begin{array}{ll}
\therefore & x+4 \times(-2)=-2 \\
& x-8=-2 \\
\therefore & x=8-2=+6
\end{array}\)
Let \(y\) be the oxidation number of Cr in \(\mathrm{K}_2 \mathrm{Cr}_2 \mathrm{O}_7\)
\(\begin{array}{ll}
\therefore \quad & 2 \times(+1)+2(y)+7 \times(-2)=0 \\
& +2+2 y-14=0 \\
& 2 y=12 \\
\therefore \quad & y=+6
\end{array}\)
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