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MHT CET · Chemistry · Solutions

Calculate the osmotic pressure of 0.03 mole of non electrolyte solute dissolved in \(0.1 \mathrm{dm}^3\) of water at \(300 \mathrm{~K}\left[\mathrm{R}=0.0821 \mathrm{dm}^3 \mathrm{~atm} \mathrm{~mol}^{-1} \mathrm{~K}^{-1}\right]\)

  1. A 7.4 atm
  2. B \(6 \cdot 4 \mathrm{~atm}\)
  3. C 8.0 atm
  4. D 5.6 atm
Verified Solution

Answer & Solution

Correct Answer

(A) 7.4 atm

Step-by-step Solution

Detailed explanation

\(\Pi = \frac{n}{V} R T\) \(\Pi = \frac{0.03 \mathrm{~mol}}{0.1 \mathrm{~dm}^3} \times 0.0821 \mathrm{~dm}^3 \mathrm{~atm} \mathrm{~mol}^{-1} \mathrm{~K}^{-1} \times 300 \mathrm{~K}\)