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MHT CET · Chemistry · Ionic Equilibrium

Calculate the \([\mathrm{OH}]\) if pOH of solution is 4.94

  1. A \(2.356 \times 10^{-5} \mathrm{M}\)
  2. B \(1.881 \times 10^{-5} \mathrm{M}\)
  3. C \(1.417 \times 10^{-5} \mathrm{M}\)
  4. D \(1.148 \times 10^{-5} \mathrm{M}\)
Verified Solution

Answer & Solution

Correct Answer

(D) \(1.148 \times 10^{-5} \mathrm{M}\)

Step-by-step Solution

Detailed explanation

\(\begin{array}{ll} & \mathrm{pOH}=-\log _{10}\left[\mathrm{OH}^{-}\right] \\ \therefore \quad & \log _{10}\left[\mathrm{OH}^{-}\right]=-4.94 \\ \therefore \quad & {\left[\mathrm{OH}^{-}\right]=10^{(-4.94)}=1.148 \times 10^{-5} \mathrm{M}}\end{array}\)