MHT CET · Chemistry · Ionic Equilibrium
Calculate the \([\mathrm{OH}]\) if pOH of solution is 4.94
- A \(2.356 \times 10^{-5} \mathrm{M}\)
- B \(1.881 \times 10^{-5} \mathrm{M}\)
- C \(1.417 \times 10^{-5} \mathrm{M}\)
- D \(1.148 \times 10^{-5} \mathrm{M}\)
Answer & Solution
Correct Answer
(D) \(1.148 \times 10^{-5} \mathrm{M}\)
Step-by-step Solution
Detailed explanation
\(\begin{array}{ll} & \mathrm{pOH}=-\log _{10}\left[\mathrm{OH}^{-}\right] \\ \therefore \quad & \log _{10}\left[\mathrm{OH}^{-}\right]=-4.94 \\ \therefore \quad & {\left[\mathrm{OH}^{-}\right]=10^{(-4.94)}=1.148 \times 10^{-5} \mathrm{M}}\end{array}\)
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