MHT CET · Chemistry · States of Matter
Calculate the number of moles of the gas having volume 2.5 liter at \(300 \mathrm{~K}\) and \(4.5 \mathrm{~atm}\) ? \(\left(\mathrm{R}=0.0821 \mathrm{~atm} \mathrm{dm}^3 \mathrm{~K}^{-1} \mathrm{~mol}^{-1}\right)\)
- A \(0.62\)
- B \(0.46\)
- C \(0.56\)
- D \(0.70\)
Answer & Solution
Correct Answer
(B) \(0.46\)
Step-by-step Solution
Detailed explanation
\(\begin{aligned} & \mathrm{PV}=\mathrm{nRT} \\ & 4.5 \times 2.5=\mathrm{n} \times 0.0821 \times 300 \\ & \mathrm{n}=0.46\end{aligned}\)
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