MHT CET · Chemistry · Some Basic Concepts of Chemistry
Calculate the number of \(\mathrm{Ca}^{2+}\) ion in 222 g anhydrous calcium chloride? (At. mass \(\mathrm{Ca}=40, \mathrm{Cl}=35 \cdot 5\) )
- A \(\mathrm{N}_{\mathrm{A}}\)
- B \(2 \mathrm{~N}_{\mathrm{A}}\)
- C \(3 \mathrm{~N}_{\mathrm{A}}\)
- D \(4 \mathrm{~N}_{\mathrm{A}}\)
Answer & Solution
Correct Answer
(B) \(2 \mathrm{~N}_{\mathrm{A}}\)
Step-by-step Solution
Detailed explanation
Molar mass of \(\mathrm{CaCl_2} = 40 + 2 \times 35.5 = 111 \mathrm{~g/mol}\) Moles of \(\mathrm{CaCl_2} = \frac{222 \mathrm{~g}}{111 \mathrm{~g/mol}} = 2 \mathrm{~mol}\)
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