MHT CET · Chemistry · Some Basic Concepts of Chemistry
Calculate the number of atoms present in unit cell of an element having molar mass \(190 \mathrm{~g} \mathrm{~mol}^{-1}\) and density \(20 \mathrm{~g} \mathrm{~cm}^{-3}\). \(\left[\mathrm{a}^3 \cdot \mathrm{N}_{\mathrm{A}}=38 \mathrm{~cm}^3 \mathrm{~mol}^{-1}\right]\)
- A \(1\)
- B \(2\)
- C \(6\)
- D \(4\)
Answer & Solution
Correct Answer
(D) \(4\)
Step-by-step Solution
Detailed explanation
Density \((\rho)=\frac{M \mathrm{n}}{\mathrm{a}^3 \mathrm{~N}_{\mathrm{A}}}\)
\(\begin{aligned}
& 20=\frac{190 \times \mathrm{n}}{38} \\
& \mathrm{n}=\frac{20 \times 38}{190}=4
\end{aligned}\)
\(\begin{aligned}
& 20=\frac{190 \times \mathrm{n}}{38} \\
& \mathrm{n}=\frac{20 \times 38}{190}=4
\end{aligned}\)
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