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MHT CET · Chemistry · Solid State

Calculate the number of atoms present in unit cell if an element having molar mass \(23 \mathrm{~g} \mathrm{~mol}^{-1}\) and density \(0.96 \mathrm{~g} \mathrm{~cm}^{-3}\). \(\left[\mathrm{a}^3 \cdot \mathrm{N}_{\mathrm{A}}=48 \mathrm{~cm}^3 \mathrm{~mol}^{-1}\right]\)

  1. A 1
  2. B 2
  3. C 4
  4. D 6
Verified Solution

Answer & Solution

Correct Answer

(B) 2

Step-by-step Solution

Detailed explanation

\(
\begin{aligned}
& \text {Density }(\rho)=\frac{\mathrm{nM}}{\mathrm{a}^3 \mathrm{~N}_{\mathrm{A}}} \\
& 0.96=\frac{\mathrm{n} \times 23}{48} \\
& \mathrm{n}=\frac{0.96 \times 48}{23}=2.003
\end{aligned}
\)
Number of atoms present in unit cell \(=2\)