MHT CET · Chemistry · Solid State
Calculate the number of atoms present in 1 g of an element if it forms fcc unit cell structure. [ \(\varrho \times \mathrm{a}^3=6.8 \times 10^{-22} \mathrm{~g}\) ]
- A \(7.125 \times 10^{21}\)
- B \(4.548 \times 10^{21}\)
- C \(6.815 \times 10^{21}\)
- D \(5.882 \times 10^{21}\)
Answer & Solution
Correct Answer
(D) \(5.882 \times 10^{21}\)
Step-by-step Solution
Detailed explanation
Number of atoms in 1 fcc unit cell \(= 4\) Mass of 1 unit cell \(= 6.8 \times 10^{-22} \mathrm{~g}\)
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