MHT CET · Chemistry · Solid State
Calculate the number of atoms in 5.4 g metal forming fcc structure \(\left[\varrho \times a^3=7 \cdot 2 \times 10^{-22} \mathrm{~g}\right]\)
- A \(3.0 \times 10^{22}\)
- B \(1.5 \times 10^{22}\)
- C \(4.5 \times 10^{22}\)
- D \(6.0 \times 10^{22}\)
Answer & Solution
Correct Answer
(A) \(3.0 \times 10^{22}\)
Step-by-step Solution
Detailed explanation
Number of atoms \( = \frac{\text{Total mass}}{\text{Mass of one unit cell}} \times \text{Atoms per unit cell}\) \( = \frac{5.4 \text{ g}}{7.2 \times 10^{-22} \text{ g}} \times 4 \)
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